18. Continuity

18.1 Definition:

Fix a Metric Space $\QTR{Large}{(M,d)}$ and a point MATH

  1. Given MATH0 we define the open ball of radius MATH around $\QTR{Large}{x,}$ MATH MATH

  2. We say MATH is open if for any MATH there exist an MATH0 such that MATH

  3. The set of open sets is called the Topology defined by the Metric.

18.2 Theorem:

In a Metric Space $\QTR{Large}{(M,d)}$

  1. $\QTR{Large}{M}$ and MATH (the empty set) is open

  2. Let MATH be an arbitrary set of open sets, then MATH is also open.

  3. Let MATH be a finite set of open sets, then MATH is also open.

Proof:

1. and 2. follow directly from the definitions, however if you haven't been through this material you should write down the details.

3. makes use of the observation that if MATH then MATH. Choose MATH . Let

MATH . We have MATH for all $\QTR{Large}{i}$ hence MATH.

18.2.1 Exercise: Show that MATH is open for any MATH0.


Solution:

For every MATH . We need to find some MATH0 such that MATHLet MATHand MATHFor every MATH . We have

MATH.

Thus MATH since this is true for any $\QTR{Large}{z.} $ we have MATH


18.3 Definition:

Given Metric Spaces MATH ,MATH and a function MATH. We say that $\QTR{Large}{f}$ is continuous a point $\QTR{Large}{x\in }$ MATH if given any MATH0 there is a MATH0 such that

MATH.

We say that $\QTR{Large}{f}$ is continuous if it is continuous at every point.

Exercise: Convince yourself that for MATH this is just the usual MATH definition.

18.3.1 Theorem:

Given Metric Spaces MATH ,MATH ,a function MATH is continuous if and only for every open set MATH

MATH is open in MATH

Proof:

Assignment: To be turned in one week from today.


Solution:

MATH

Suppose for every open set MATH we know that MATH is open in MATH Suppose we are given MATH0 and $\QTR{Large}{x\in }$ MATH. We need to find MATH0 such that MATH. But by 18.2.1 we know that MATH is open. Hence MATH is open. Hence we can find MATH0 such that MATH . Or, equivalently, MATH

MATH

Suppose MATH is continuous and MATH is open we need to show that MATH is open in MATHSuppose we are given MATH0 and $\QTR{Large}{x\in }$ MATH such that MATHSince $\QTR{Large}{f}$ is continuous, we can find MATH0 such that $\ $

MATH Thus MATH


18.4 Corollary

Suppose we have two metrics MATH and MATH defined on MATH that produce the same Topology (open sets). Then a function MATH is continuous with respect to the metric MATH if and only if it is continuous with respect to the metric MATH

Exercise: State and prove the corresponding appropriate result for MATH

18.5 Corollary

Suppose we have three Metric Spaces MATH ,MATH , and MATH suppose MATH and MATH are continuous, then so is MATH

Proof:

Let MATH be open. Since $\QTR{Large}{g}$ is continuous so is MATH is open in MATH and since $\QTR{Large}{f}$ is continuous

so is MATH

18.6 Notation:

Given Metric Spaces MATH ,MATH we use the notation MATH ,MATH to represent the set of continuous functions from MATH to MATH

18.7 Lemma:

  1. Let MATH be a metric space and MATH be a continuous function from MATH to MATH , then
          MATH ,MATH ,MATH
    where, as in 0.1, MATH

  2. Let MATH be a metric space and MATH be a continuous function from MATH to MATH, then
          MATH ,MATH ,MATH
    where MATH

Proof: Immediate from 18.5


Returning to 17.3 The Circle, MATH we want to show that the three Metrics

  1. MATH

  2. MATH

  3. MATH

produce the same set of continuous functions.

Assignment: (To be turned in one week from today) We could simply use 18.4 (do this!)


Solution:

We need to show that MATH is open with respect to MATH iff it is open with respect to MATHiff it is open with respect to MATH

To accomplish this, it suffices to show that if we are given $\QTR{Large}{x\in }$ MATHand MATH0 we can find, in sequence MATH0 , MATH0 and MATH0 such that

MATH

One note: there is no loss of generality in assuming that the MATHor MATH we work with for the next computation are smaller than the one we initially are given, or compute.

Beginning with a simple case, let MATHSuppose we know that MATH then we know MATH

So MATH .

The hardest calculations involve MATH . Given MATH0 , I need find MATH0

$\vspace{1pt}$

MATH

In computing MATH we make use of the inequality MATH for small positive values of MATH.

Let MATH

then $\QTR{Large}{g(}$0$\QTR{Large}{)=\ }$0 and MATH0 for small MATH

Now let MATH . Suppose MATH

we have MATH or MATH

The computation of MATH follows in a similar fashion using the observation that MATH for MATH 0.

Let MATH and assume that MATH, we have

MATH


but it will be useful in the sequel if we go about it in a slightly different way.

18.8 Lemma:

The identity map MATH is continuous with respect to any pair of the above Metrics.

Proof:

Using MATH to denote the identity map when considered as a map between specific Metric spaces, it is sufficient to show

  1. MATH

  2. MATH

  3. MATH

are continuous since for example, MATH is continuous by 18.5. Since all three arguments are similar we give the details of 1. Choose MATH0 and MATH . Let MATH . Suppose MATH . MATH we have MATHFor large radii points can be far apart in distance yet close in terms of angle.

18.9 Theorem:

Let MATH be a map of sets. suppose MATH is equipped with a Metric $\QTR{Large}{d_{1}}$. Then if $\QTR{Large}{f}$ is continuous with respect to any of the three metrics MATH is continuous with respect to the other two.

Proof:

Suppose MATH ,MATH

As a set map MATH on the other hand, by 18.7 MATH is continuous for MATH